(4a^2+7a-12)+(-9a^2+2a-6)=0

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Solution for (4a^2+7a-12)+(-9a^2+2a-6)=0 equation: 



(4a^2+7a-12)+(-9a^2+2a-6)=0

We get rid of parentheses

-9a^2+4a^2+2a+7a-6-12=0

We add all the numbers together, and all the variables

-5a^2+9a-18=0

a = -5; b = 9; c = -18;
Δ = b2-4ac
Δ = 92-4·(-5)·(-18)
Δ = -279
Delta is less than zero, so there is no solution for the equation

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